21x^2+22=-104

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Solution for 21x^2+22=-104 equation: 



21x^2+22=-104

We move all terms to the left:

21x^2+22-(-104)=0

We add all the numbers together, and all the variables

21x^2+126=0

a = 21; b = 0; c = +126;
Δ = b2-4ac
Δ = 02-4·21·126
Δ = -10584
Delta is less than zero, so there is no solution for the equation

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